In the given figure, AB is the diameter of the circle with centre O.
If ∠ADC = 32°, find angle BOC
Arc AC subtends ∠AOC at the centre and ∠ADC at the remaining part Of the circle ∴ ∠AOC = 2 ∠ADC ⇒ ∠AOC = 2 × 32° = 64° Since ∠AOC and ∠BOC are linear pair, we have ∠AOC + ∠BOC = 180° ⇒ 64° + BOC = 180° ⇒ ∠BOC = 180° ⇒ ∠BOC = 180° - 64° ⇒ ∠BOC = 116°
Solution In the Given Figure, Ab is the Diameter of the Circle with Centre O. If ∠Adc = 32°, Find Angle Boc Concept: Arc and Chord Properties - the Angle that an Arc of a Circle Subtends at the Center is Double that Which It Subtends at Any Point on the Remaining Part of the Circle.