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The Following Figure Shows a Circle with Pr as Its Diameter. If Pq = 7 Cm and Qr = 3rs = 6 Cm, Find the Perimeter of the Cyclic Quadrilateral Pqrs. - Mathematics

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Question

The following figure shows a circle with PR as its diameter.
If PQ = 7 cm and QR = 3RS = 6 cm, find the perimeter of the cyclic quadrilateral PQRS.

Solution

In the figure, PQRS is a cyclic quadrilateral in which PR is a diameter
PQ = 7 cm
QR = 3 RS = 6 cm
3 RS = 6 cm ⇒ RS = 2 cm

Now in ∆PQR,
∠Q = 90°        [Angles in a semi circle]

 `PR^ 2 = PQ^2 + QR^2` [Pythagoras theorem]

          = `72^2 + 62^2`
           = 49 + 36
           = 85

Again in right= `ΔPSQ,  PR^2 =PS^2 + RS^2`  

 `85 = PS^2 + 2^2`

`PS^2 = 85 - 4 = 81 = (9)^2`
  PS = 9cm
Now, perimeter of quad PQRS = PQ + QR + RS + SP
                                            = (7 + 9 + 6 )cm
                                            = 24

  Is there an error in this question or solution?
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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 17: Circles
Exercise 17(C) | Q: 16 | Page no. 267
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The Following Figure Shows a Circle with Pr as Its Diameter. If Pq = 7 Cm and Qr = 3rs = 6 Cm, Find the Perimeter of the Cyclic Quadrilateral Pqrs. Concept: Arc and Chord Properties - Angle in a Semi-circle is a Right Angle.
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