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In the Given Figure, Ab is a Diameter of the Circle with Centre O. Do is Parallel to Cb and ∠Dcb = 120°. Calculate: ∠Dab, Also Show that the δAod is an Equilateral - Mathematics

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Question

In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and ∠DCB = 120°.
Calculate :  ∠DAB 
Also show that the ΔAOD is an equilateral triangle .

Solution


ABCD is a cyclic quadrilateral

∴ ∠DCB + ∠DAB = 180°

(pair of opposite angles in a cyclic quadrilateral are supplementary)

⇒ ∠DAB =180° -120° = 60°

  Is there an error in this question or solution?
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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 17: Circles
Exercise 17(A) | Q: 38.1 | Page no. 260
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In the Given Figure, Ab is a Diameter of the Circle with Centre O. Do is Parallel to Cb and ∠Dcb = 120°. Calculate: ∠Dab, Also Show that the δAod is an Equilateral Concept: Arc and Chord Properties - Angle in a Semi-circle is a Right Angle.
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