CBSE (Commerce) Class 12CBSE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution for If Y = Loge X, Then Find ∆Y When X = 3 and ∆X = 0.03 ? - CBSE (Commerce) Class 12 - Mathematics

Login
Create free account


      Forgot password?

Question

If y = loge x, then find ∆y when x = 3 and ∆x = 0.03 ?

Solution

We have

\[x = 3\]

\[ ∆ x = 0 . 03\]

\[y = \log_e x\]

\[\text { For } x = 3, \]

\[y = \log_e 3\]

\[\text { Also }, \frac{dy}{dx} = \frac{1}{x}\]

\[ \Rightarrow \left( \frac{dy}{dx} \right)_{x = 3} = \frac{1}{3}\]

\[ \Rightarrow ∆ y = dy = \frac{dy}{dx}dx = \frac{1}{3} \times 0 . 03 = 0 . 01\]

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Mathematics for Class 12 by R D Sharma (Set of 2 Volume) (2018-19 Session) (with solutions)
Chapter 14: Differentials, Errors and Approximations
Q: 2 | Page no. 12

Video TutorialsVIEW ALL [2]

Solution for question: If Y = Loge X, Then Find ∆Y When X = 3 and ∆X = 0.03 ? concept: Approximations. For the courses CBSE (Commerce), CBSE (Arts), PUC Karnataka Science, CBSE (Science)
S
View in app×