#### Question

If the ratio of base radius and height of a cone is 1 : 2 and percentage error in radius is λ %, then the error in its volume is

(a) λ %

(b) 2 λ %

(c) 3 λ %

(d) none of these

#### Solution

(c) 3 *λ* %

Let the radius of the cone be *x, *the height be 2*x* and the volume be y.

\[\frac{∆ x}{x} = \lambda % \]

\[ \Rightarrow y = \frac{1}{3}\pi x^2 \times 2x = \frac{2}{3}\pi x^3 \]

\[ \Rightarrow \frac{dy}{dx} = 2\pi x^2 \]

\[ \Rightarrow \frac{∆ y}{y} = \frac{2\pi x^2}{y}dx = \frac{3}{x} \times \lambda x\]

\[ \Rightarrow \frac{∆ y}{y} = 3\lambda\%\]

Is there an error in this question or solution?

Solution for question: If the Ratio of Base Radius and Height of a Cone is 1 : 2 and Percentage Error in Radius is λ %, Then the Error in Its Volume is (A) λ % (B) 2 λ % (C) 3 λ % (D) None of These concept: Approximations. For the courses CBSE (Science), PUC Karnataka Science, CBSE (Arts), CBSE (Commerce)