#### Question

A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?

#### Solution

Time taken by the sonar pulse to return, *t *= 1.02 s

Speed of sound in salt water, *v *= 1531 m s^{−1}

Total distance covered by the sonar pulse = Speed of sound × Time taken

Total distance covered by the sonar pulse = 1.02 x 1531 = 1561.62 m .....(i)

Let *d* be the distance of the cliff from the submarine.

Total distance covered by the sonar pulse = 2*d*

`rArr 2d=1561.62" [From (i)]"`

`rArrd=780.81 m`

Is there an error in this question or solution?

Solution A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff? Concept: Applications of Ultrasound - SONAR.