#### Question

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

#### Solution

The initial count of bacteria is given as 5,06,000.

Bacteria at the end of 2 hours = `506000 (1 + 2.5/100)^2`

= `506000(1 + 1/40)^2 = 506000 xx 41/40 xx 41/40`

= 531616.25 = 531616 (approx)

Thus, the count of bacteria at the end of 2 hours will be 5,31,616 (approx.).

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Solution In a Laboratory, the Count of Bacteria in a Certain Experiment Was Increasing at the Rate of 2.5% per Hour. Find the Bacteria at the End of 2 Hours If the Count Was Initially 5,06,000. Concept: Applications of Compound Interest Formula.