#### Question

Prove that:

\[\frac{\sin^2 \theta}{\cos\theta} + \cos\theta = \sec\theta\]

#### Solution

\[\frac{\sin^2 \theta}{\cos\theta} + \cos\theta\]

\[ = \frac{\sin^2 \theta + \cos^2 \theta}{\cos\theta}\]

\[ = \frac{1}{\cos\theta}\]

\[ = \sec\theta\]

Is there an error in this question or solution?

Solution Prave That: Sin 2 θ Cos θ + Cos θ = Sec Concept: Application of Trigonometry.