Maharashtra State Board course SSC (English Medium) Class 10th Board Exam
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Prave That: Cot θ + Tan θ = C O S E C θ Sec θ - Geometry

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Question

Prove that:

\[\cot\theta + \tan\theta = cosec\theta \sec\theta\]

Solution

\[\cot\theta + \tan\theta\]

\[ = \frac{\cos\theta}{\sin\theta} + \frac{\sin\theta}{\cos\theta}\]

\[ = \frac{\sin^2 \theta + \cos^2 \theta}{\sin\theta\cos\theta}\]

\[ = \frac{1}{\sin\theta\cos\theta} \left( \sin^2 \theta + \cos^2 \theta = 1 \right)\]

\[ = \frac{1}{\sin\theta} \times \frac{1}{\cos\theta}\]

\[ = \text{ cosec } \theta\sec\theta\]

  Is there an error in this question or solution?

APPEARS IN

 Balbharati Solution for Balbharati Class 10 Mathematics 2 Geometry (2018 to Current)
Chapter 6: Trigonometry
Practice set 6.1 | Q: 6.05 | Page no. 131
Solution Prave That: Cot θ + Tan θ = C O S E C θ Sec θ Concept: Application of Trigonometry.
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