#### Question

A man goes 15 metres due west and then 8 metres due north. How far is he from the starting point?

#### Solution

Let the starting point of the man be O and final point be A.

∴ In ΔABO, by Pythagoras theorem AO^{2} = AB^{2} + BO^{2}

⇒ AO^{2} = 8^{2} + 15^{2}

⇒ AO^{2} = 64 + 225 = 289

⇒ AO = `sqrt289` = 17m

∴ He is 17m far from the starting point.

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#### APPEARS IN

Solution A Man Goes 15 Metres Due West and Then 8 Metres Due North. How Far is He from the Starting Point? Concept: Application of Pythagoras Theorem in Acute Angle and Obtuse Angle.