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**Answer the following question.**

With the help of a suitable circuit diagram prove that the reciprocal of the equivalent resistance of a group of resistances joined in parallel is equal to the sum of the reciprocals of the individual resistances.

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#### Solution

Let there are n resistances, each of value RI, R2 Rn, respectively, are connected in parallel to a battery of voltage V. if the equivalent resistance of the circuit is Req, then-current drawn from

`"i" = "V"/"R"_("eq")`

the battery is

The total current /then divides into Ii, i2, i3 in, respectively in the given resistors. As all the resistances are connected in parallel, hence the voltage across each resistor is V Volt. Now we can write,

i= i_{1} + i_{2} + i_{3 }+ ...........+ i_{eq}

`"V"/"R"_("eq")="V"/"R"_1+"V"/"R"_2+"V"/"R"_3.......+ "V"/"R"_"n"` ......(1)

From eq. 1,

`1/"R"_("eq")=1/"R"_1+1/"R"_2+1/"R"_3......+1/"R"_"n"`

Hence, reciprocal of the equivalent resistance is equal to the sum of reciprocal of each resistor joined in parallel