#### Question

Numerical

**Answer the following question.**

Two identical point charges, q each, are kept 2m apart in the air. A third point charge Q of unknown magnitude and sign is placed on the line joining the charges such that the system remains in equilibrium. Find the position and nature of Q.

#### Solution

`(K(q)(Q))/x = (-K(q)(q))/2`

⇒ `Q = (-qx)/2`

`because (KqQ)/x = (KQq)/y`

x = y

x + y = 2

∴ x = y = 1

`Q = (-q)/2`

Concept: Equipotential Surfaces

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