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Numerical
Answer the following question.
State Bohr's quantization condition of angular momentum. Calculate the shortest wavelength of the Bracket series and state to which part of the electromagnetic spectrum it belongs.
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Solution
According to Bohr's quantization, the electrons revolve around the nucleus only in those orbits for which the angular momentum is the integral multiple of
`h/(2pi)`
`L = (nh)/2`
for bracket series n2 = ∞
`1/λ = R_HZ^2{1/4^2 - 1/∞}`
`1/λ = R_H/16`
`λ = 16/R_H = 14.58 xx 10^-7`m
This wavelength belongs to the infrared region.
Concept: De Broglie’S Explanation of Bohr’S Second Postulate of Quantisation
Is there an error in this question or solution?
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