#### Question

Numerical

**Answer the following question.**

State Bohr's quantization condition of angular momentum. Calculate the shortest wavelength of the Bracket series and state to which part of the electromagnetic spectrum it belongs.

#### Solution

According to Bohr's quantization, the electrons revolve around the nucleus only in those orbits for which the angular momentum is the integral multiple of

`h/(2pi)`

`L = (nh)/2`

for bracket series n_{2} = ∞

`1/λ = R_HZ^2{1/4^2 - 1/∞}`

`1/λ = R_H/16`

`λ = 16/R_H = 14.58 xx 10^-7`m

This wavelength belongs to the infrared region.

Is there an error in this question or solution?

Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads