Answer in Brief
Answer the following question.
For s-block and p-block elements show that the number of valence electrons is equal to its group number.
- 3Li is an s-block element and its electronic configuration is 1s2 2s1. Since it has one valence electron, it is placed in group 1.
- Therefore, for s-block elements, group number = number of valence electrons.
- However, for p-block elements, group number = 18 – number of electrons required to attain complete octet.
- 7N is a p-block element and its electronic configuration is 1s2 2s2 2p3. Since it has five electrons in its valence shell, it is short of three electrons to complete its octet.
- Therefore, its group number = 18 – 3 = 15.
Concept: Periodic Table and Electronic Configuration
Is there an error in this question or solution?