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Answer the following question. Calculate the maximum work when 24 g of O2 are expanded isothermally and reversibly from the pressure of 1.6 bar to 1 bar at 298 K. - Chemistry

Sum

Answer the following question.

Calculate the maximum work when 24 g of O2 are expanded isothermally and reversibly from the pressure of 1.6 bar to 1 bar at 298 K.

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Solution

Given:
Mass of O2 = 24 g
Initial pressure = P1 = 1.6 bar
Final pressure = P2 = 1 bar
Temperature = T = 298 K

To find: Maximum work (Wmax)

Formula: `"W"_"max" = - 2.303  "nRT"  log_10  "P"_1/"P"_2`

Calculation:

Number of moles of O2 = n = `(24 "g")/(32 "g  mol"^-1)` = 0.75 mol

Gas constant = R = 8.314 J K–1 mol–1

Now, using formula,

`"W"_"max" = - 2.303  "nRT"  log_10  "P"_1/"P"_2`

= - 2.303 × 0.75 mol × 8.314 J K-1mol-1 × 298 K × `log_10  1.6/1`

= - 2.303 × 0.75 × 8.314 J × 298 × 0.2041

= - 873.4 J

The maximum work done is – 873.4 J.

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APPEARS IN

Balbharati Chemistry 12th Standard HSC Maharashtra State Board
Chapter 4 Chemical Thermodynamics
Exercise | Q 4.07 | Page 88
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