Advertisement Remove all ads

Answer the following: Predict whether the following reaction would occur spontaneously under standard state condition. Ca(s)+Cd(aq)2+→Ca(aq)2++Cd(s) - Chemistry

Advertisement Remove all ads
Advertisement Remove all ads
Short Note

Answer the following:

Predict whether the following reaction would occur spontaneously under standard state condition.

`"Ca"_(("s")) + "Cd"_(("aq"))^(2+) -> "Ca"_(("aq"))^(2+) + "Cd"_(("s"))`

Advertisement Remove all ads

Solution

`"Ca"_(("s")) + "Cd"_(("aq"))^(2+) -> "Ca"_(("aq"))^(2+) + "Cd"_(("s"))`

At anode: `"Ca"_(("s")) -> "Ca"_(("aq"))^(2+) + 2"e"^(-)`

At cathode: `"Ca"_(("aq"))^(2+) + 2"e"^(-) -> "Cd"_(("s"))`

From the electrochemical series we have,

`"E"_"Ca"^circ` = - 2.866 V and `"E"_"Cd"^circ` = - 0.403 V

For cell having Ca as anode and Cd as cathode.

`"E"_"cell"^circ = "E"_"Cd"^circ - "E"_"Ca"^circ`

= - 0.403 V - (- 2.866) V

`"E"_"cell"^circ` = 2.463 V

Emf of cell being positive, the given cell reaction is spontaneous.

Concept: Electrode Potential and Cell Potential
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 5 Electrochemistry
Exercises | Q 4.14 | Page 119
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×