# Answer the following: Predict whether the following reaction would occur spontaneously under standard state condition. Ca(s)+Cd(aq)2+→Ca(aq)2++Cd(s) - Chemistry

Short Note

Predict whether the following reaction would occur spontaneously under standard state condition.

"Ca"_(("s")) + "Cd"_(("aq"))^(2+) -> "Ca"_(("aq"))^(2+) + "Cd"_(("s"))

#### Solution

"Ca"_(("s")) + "Cd"_(("aq"))^(2+) -> "Ca"_(("aq"))^(2+) + "Cd"_(("s"))

At anode: "Ca"_(("s")) -> "Ca"_(("aq"))^(2+) + 2"e"^(-)

At cathode: "Ca"_(("aq"))^(2+) + 2"e"^(-) -> "Cd"_(("s"))

From the electrochemical series we have,

"E"_"Ca"^circ = - 2.866 V and "E"_"Cd"^circ = - 0.403 V

For cell having Ca as anode and Cd as cathode.

"E"_"cell"^circ = "E"_"Cd"^circ - "E"_"Ca"^circ

= - 0.403 V - (- 2.866) V

"E"_"cell"^circ = 2.463 V

Emf of cell being positive, the given cell reaction is spontaneous.

Concept: Electrode Potential and Cell Potential
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#### APPEARS IN

Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 5 Electrochemistry
Exercises | Q 4.14 | Page 119