# Answer the following in one sentence : Calculate the pH of 0.01 M sulphuric acid. - Chemistry

Sum

Answer the following in one sentence :

Calculate the pH of 0.01 M sulphuric acid.

#### Solution

Given: Concentration of sulphuric acid = 0.01 M

To find: pH

Formula: pH = -"log"_10["H"_3"O"^+]

Calculation:

Sulphuric acid (H2SO4) is a strong acid. It dissociates almost completely in the water as:

$\ce{H2SO4_{(aq)} + 2H2O_{(l)} -> 2H3O^+_{ (aq)} + SO^{2-}_{4(aq)}}$

Hence, [H3O+] = 2 × c = 2 × 0.01 M = 2 × 10-2 M

From formula (i),

pH = -log10[H3O+] = -log10[2 × 10-2] = -"log"_10"2" - "log"_10"10"^-2

= -"log"_10"2" + 2 = 2 - 0.3010

pH = 1.699

The pH of 0.01 M sulphuric acid is 1.699.

Concept: The pH Scale
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#### APPEARS IN

Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 3 Ionic Equilibria
Exercises | Q 2.07 | Page 61