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Answer the following in one or two sentences. A 0.1 m solution of K2SO4 in water has a freezing point of – 4.3 °C. What is the value of van’t Hoff factor if Kf for water is 1.86 K kg mol–1? - Chemistry

Sum

Answer the following in one or two sentences.

A 0.1 m solution of K2SO4 in water has a freezing point of – 4.3 °C. What is the value of van’t Hoff factor if Kf for water is 1.86 K kg mol–1?

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Solution

Given: Molality of K2SO4 solution = m = 0.1 m
Freezing point of solution = Tf = – 4.3 °C
Kf of water = 1.86 K kg mol–1

To find: van’t Hoff factor

Formula: ΔTf = i Kf m

Calculation: 

ΔTf = `"T"_"f"^0` - Tf

= 0 °C - (- 4.3 °C) = 4.3 °C = 4.3 K

Now, using formula,

ΔTf = i Kf m

∴ i = `(triangle "T"_"f")/("K"_"f" * "m")`

`= (4.3 "K")/(1.86 "k kg mol"^-1 xx 0.1 "mol kg"^-1)`

= 23.1

The value of van’t Hoff factor is 23.1.

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APPEARS IN

Balbharati Chemistry 12th Standard HSC Maharashtra State Board
Chapter 2 Solutions
Exercise | Q 2.04 | Page 45
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