Maharashtra State BoardHSC Arts 11th
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Answer the following: Find the trigonometric functions of : −330° - Mathematics and Statistics

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Sum

Answer the following:

Find the trigonometric functions of :

−330°

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Solution

Angle of measure (– 330°) :

Let m∠XOA = −330°

Its terminal arm (ray OA) intersects the standard unit circle at P(x, y).

Draw seg PM perpendicular to the X-axis.

∴ ΔOMP is a 30° – 60° – 90° triangle.

OP = 1

OM = `sqrt(3)/2"OP"`

= `sqrt(3)/2(1)`

= `sqrt(3)/2`

PM = `1/2"OP"`

= `1/2(1)`

= `1/2`

Since point P lies in the 1st quadrant,

x > 0, y > 0

∴ x = OM = `sqrt(3)/2 and y = "PM" = 1/2`

∴ P ≡ `(sqrt(3)/2, 1/2)`

sin (−330°) = y = `1/2`

cos (−330°) = x = `sqrt(3)/2`

tan (−330°) = `y/x = (1/2)/(sqrt(3)/2) = 1/sqrt(3)`

cosec (−330°) = `1/y = 1/((1/2))` = 2

sec (−330°) = `1/x = 1/((sqrt(3)/2)) = 2/sqrt(3)`

cot (−330°) = `x/y = (sqrt(3)/2)/((1/2)) = sqrt(3)`

Concept: Trigonometric Functions of Specific Angles
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APPEARS IN

Balbharati Mathematics and Statistics 1 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 2 Trigonometry - 1
Miscellaneous Exercise 2 | Q II. (1) l. | Page 33
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