Maharashtra State BoardHSC Science (General) 11th
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Answer the following: Find tenth term in the expansion of (2x2+1x)12 - Mathematics and Statistics

Sum

Answer the following:

Find tenth term in the expansion of `(2x^2 + 1/x)^12`

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Solution

We know that, the (r + 1)th term in the expansion of (a + b)n is

tr+1 = nCr, an-r br

Here a = 2x2, b = `1/x`, n = 12 and for t10, r = 9

 ∴ tenth term in the expansion of `(2x^2 + 1/x)^12`

=t10 = `""^12"C"_9 (2x^2)^(12 - 9) (1/x)^9`

= `""^12"C"_3 (2x^2)^3 (1/x)^9`  ...[∵ nCr = nCn-r]

= `(12 xx 11 xx 10)/(1 xx 2 xx 3) xx 8x^6 xx 1/x^9`

= `1760/x^3`

Concept: General Term in Expansion of (a + b)n
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APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 4 Methods of Induction and Binomial Theorem
Miscellaneous Exercise 4 | Q II. (7) | Page 85
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