Answer the following Europium and ytterbium behave as good reducing agents in the +2 oxidation state explain. - Chemistry

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Answer in Brief

Answer the following

Europium and ytterbium behave as good reducing agents in the +2 oxidation state explain.

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Solution

i. Europium (Eu) and Ytterbium (Yb) show +2 oxidation states. Their electronic configurations are given below:

Eu = [Xe] 4f7 6s2 ; Eu2+ = [Xe] 4f7

Yb = [Xe] 4f14 6s2 ; Yb2+ = [Xe] 4f14

ii. It is clear from the configuration of Eu that Eu2+ is favoured by its half-filled f-subshell. But it can be easily converted into stable Eu3+ by the loss of an electron. Due to this reason, Eu2+ is a good reducing agent.

iii. Similarly, Yb2+ ion is stabilized due to completely filled f-subshell. It can be easily converted into Yb3+ by the loss of an electron. Due to this reason, Yb2+ is a good reducing agent.

Concept: Inner Transition (f-block) Elements: Lanthanoids and Actinoids
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Chapter 8: Transition and Inner transition Elements - Exercises [Page 191]

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Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 8 Transition and Inner transition Elements
Exercises | Q 3.11 | Page 191
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