Advertisement Remove all ads

Answer the following Europium and ytterbium behave as good reducing agents in the +2 oxidation state explain. - Chemistry

Answer in Brief

Answer the following

Europium and ytterbium behave as good reducing agents in the +2 oxidation state explain.

Advertisement Remove all ads

Solution

i. Europium (Eu) and Ytterbium (Yb) show +2 oxidation states. Their electronic configurations are given below:

Eu = [Xe] 4f7 6s2 ; Eu2+ = [Xe] 4f7

Yb = [Xe] 4f14 6s2 ; Yb2+ = [Xe] 4f14

ii. It is clear from the configuration of Eu that Eu2+ is favoured by its half-filled f-subshell. But it can be easily converted into stable Eu3+ by the loss of an electron. Due to this reason, Eu2+ is a good reducing agent.

iii. Similarly, Yb2+ ion is stabilized due to completely filled f-subshell. It can be easily converted into Yb3+ by the loss of an electron. Due to this reason, Yb2+ is a good reducing agent.

Concept: Inner Transition (f-block) Elements: Lanthanoids and Actinoids
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 8 Transition and Inner transition Elements
Exercise | Q 3.11 | Page 191
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×