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Answer in brief. Derive the expression for PV work - Chemistry

Answer in Brief

Answer in brief.

Derive the expression for PV work.

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Solution

Pressure-volume work

  1. Consider a certain amount of gas at constant pressure P is enclosed in a cylinder fitted with a frictionless, rigid movable piston of area A. Let the volume of the gas be V1 at temperature T. This is shown in the adjacent diagram.
  2. On expansion, the force exerted by a gas is equal to area of the piston multiplied by pressure with which the gas pushes against piston. This pressure is equal in magnitude and opposite in sign to the external atmospheric pressure that opposes the movement and has its value - Pext.
    Thus,
    f =  - Pext × A       .....(1)
    where, Pext is the external atmospheric pressure.
  3. If the piston moves out a distance d, then the amount of work done is equal to the force multiplied by distance.
    W = f × d        .....(2)
    Substituting equation (1) in (2) gives
    W =  - Pext × A × d        .....(3)
  4. The product of area of the piston and distance it moves is the volume change (ΔV) in the system.
    ΔV = A × d           .....(4)
    Combining equation (3) and (4), we get
    W =  - Pext ΔV
    W = - Pext (V2 - V1)
    Where V2 is the final volume of the gas.
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APPEARS IN

Balbharati Chemistry 12th Standard HSC Maharashtra State Board
Chapter 4 Chemical Thermodynamics
Exercise | Q 3.7 | Page 88
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