Question

Answer the followiiig questions: 
Calculate the boiling point of urea solution when 6 g of urea is dissolved in 200 g of water.
(Kb for water = 0.52 K kg mol–1, bolining point of pure water = 373 K, mol. wt. of urea = 60) 

Answer 1

`T_b^o`= 373 K      M.W. of urea  = 60 g/mol

kb = 0.52  K  kg/mol 
W_urea = 6g
W_solvent = 200g
T_b = ? 
As we know 
`Delta T_b = K_bxx (W_2)/(M_2)xx1000/W_1`

`Tb - T_b^0 = Kbxx(W_2)/(M_2)xx1000/(W_1)` 

`T_b-373 =  0.52xx6/60xx 1000/200`

`T<sub>b</sub> = 373.25 K`