Answer the followiiig questions:
Calculate the boiling point of urea solution when 6 g of urea is dissolved in 200 g of water.
(Kb for water = 0.52 K kg mol–1, bolining point of pure water = 373 K, mol. wt. of urea = 60)
`T_b^o`= 373 K M.W. of urea = 60 g/mol
kb = 0.52 K kg/mol
Wurea = 6g
Wsolvent = 200g
Tb = ?
As we know
`Delta T_b = K_bxx (W_2)/(M_2)xx1000/W_1`
`Tb - T_b^0 = Kbxx(W_2)/(M_2)xx1000/(W_1)`
`T_b-373 = 0.52xx6/60xx 1000/200`
`Tb = 373.25 K`