Maharashtra State BoardHSC Commerce 11th
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Ankita's Salary was reduced by 50%. Again the reduced salary was increased by 50%. Find loss in terms of percentage. - Mathematics and Statistics

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Sum

Ankita's Salary was reduced by 50%. Again the reduced salary was increased by 50%. Find loss in terms of percentage.

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Solution

Let Ankita’s initial salary be ₹ ‘x’.

Her salary was reduced by 50%.

∴ Ankita’s salary after the reduction

= `"x"(1 - 50/100) = "x"(1 - 1/2)`

= `"x"/2`

Ankita’s reduced salary was then increased by 50%

∴ Ankita’s final salary after the increase

= `"x"/2(1 + 50/100) = "x"/2(1 + 1/2)`

= `"x"/2 xx 3/2`

= `(3"x")/4`

∴ Loss in Ankita’s salary after the decrease and increase

= `"x" - (3"x")/4 = "x"/4`

Percentage loss = `"loss in salary"/"initial salary" xx 100`

= `("x"/4)/"x" xx 100`

= `1/4 xx 100`

= 25

∴ Ankita lost 25% of her salary.

Concept: Profit and Loss
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APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 11th Standard HSC Maharashtra State Board
Chapter 9 Commercial Mathematics
Miscellaneous Exercise 9 | Q 3 | Page 144
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