In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.
If AB = 5.6 cm, AC = 6cm and DC = 3cm, find BC.
We have, In ΔABC, AD is the bisector of ∠A.
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
`rArr"BD"=(5.6xx3)/6=5.6/2=2.8 ` cm
⇒ BD = 2.8 cm
Since, BC = BD + DC
= 2.8 + 3
= 5.8 cm
∴ BC = 5.8 cm
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