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Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? - Chemistry

Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions?

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Solution

The formula of nickel oxide is Ni0.98O1.00.

Therefore, the ratio of the number of Ni atoms to the number of O atoms, 
Ni : O = 0.98 : 1.00 = 98 : 100

Now, total charge on 100 O2− ions = 100 × (−2)

= −200

Let the number of Ni2+ ions be x.

So, the number of Ni3+ ions is 98 − x.

Now, total charge on Ni2+ ions = x(+2)

= +2x

And, total charge on Ni3+ ions = (98 − x)(+3)

= 294 − 3x

Since, the compound is neutral, we can write:

2x + (294 − 3x) + (−200) = 0

⇒ −x + 94 = 0

⇒ x = 94

Therefore, number of Ni2+ ions = 94

And, number of Ni3+ ions = 98 − 94 = 4

Hence, fraction of nickel that exists as Ni2+ = 94/98

= 0.959

And, fraction of nickel that exists as  Ni3+ = 4/98

= 0.041

Alternatively, fraction of nickel that exists as Ni3+ = 1 − 0.959

= 0.041

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APPEARS IN

NCERT Class 12 Chemistry Textbook
Chapter 1 The Solid State
Q 16 | Page 31
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