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An Urn Contains 5 Red and 2 Black Balls. Two Balls Are Randomly Drawn. Let X Represents the Number of Black Balls. What Are the Possible Values of X? is X a Random Variable? - CBSE (Commerce) Class 12 - Mathematics

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Question

An urn contains 5 red and 2 black balls. Two balls are randomly drawn. Let X represents the number of black balls. What are the possible values of X? Is X a random variable?

Solution

The two balls selected can be represented as BB, BR, RB, RR, where B represents a black ball and R represents a red ball.

X represents the number of black balls.

∴X (BB) = 2

X (BR) = 1

X (RB) = 1

X (RR) = 0

Therefore, the possible values of X are 0, 1, and 2.

Yes, X is a random variable.

  Is there an error in this question or solution?

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Solution An Urn Contains 5 Red and 2 Black Balls. Two Balls Are Randomly Drawn. Let X Represents the Number of Black Balls. What Are the Possible Values of X? is X a Random Variable? Concept: Random Variables and Its Probability Distributions.
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