An Organic Substance (M = 169 Gram Mol^–1) is Dissolved in 2000 cm^3 of Water. Its Osmotic Pressure at 12°C Was Found to Be 0.54 Atm. If R = 0.0821 L Atm K^–1 Mol^–1, Calculate the Mass Of the Solute. - Chemistry

An organic substance (M = 169 gram mol–1) is dissolved in 2000 cm3 of water. Its osmotic pressure at 12°C was found to be 0.54 atm. If R = 0.0821 L atm K–1 mol–1, calculate the mass of the solute.

Solution

Given: T = 273.15 + 12 = 285.15 K
V = 2000 cm3 = 2 L
M2= 169 g mol–1
R = 0.0821 L atm K–1 mol–1
π = 0.54 atm

To find: Mass of solute (W2)

pi=(W_2RT)/(M2V)

W_2=(piM_2V)/(RT)

W_2=(0.54xx169xx2)/(0.0821xx285.15)

W_2=182.52/23.4108=7.796 g

Concept: Colligative Properties and Determination of Molar Mass - Introduction
Is there an error in this question or solution?