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An old woman decided to divide her gold among her daughter and daughters-in-law. She first kept exactly half of the gold for her daughter. Then she divided the rest of her gold among her daughters-in-law. The eldest one got 26 grams more than the youngest daughter-in-law. The middle one got twice as the youngest one. If the eldest daughter-in -law got 66 grams of gold, how much was received by the daughter?

#### Options

172 grams

186 grams

194 grams

192 grams

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#### Solution

186 grams

**Explanation:**

Eldest daughter-in-law = 66 gm of gold

Youngest daughter-in-law has = 40 gm of gold

Middle daughter-in-law has = 80 gm of gold

Altogether they have = 66 + 40 + 80 gm of gold

= 186 gm of gold

Therefore, daughter has = 186 gm of gold

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