An Old Woman Decided to Divide Her Gold Among Her Daughter and Daughters-in-law. She First Kept Exactly Half of the Gold for Her Daughter. - Logical Reasoning

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An old woman decided to divide her gold among her daughter and daughters-in-law. She first kept exactly half of the gold for her daughter. Then she divided the rest of her gold among her daughters-in-law. The eldest one got 26 grams more than the youngest daughter-in-law. The middle one got twice as the youngest one. If the eldest daughter-in -law got 66 grams of gold, how much was received by the daughter?

Options

  • 172 grams

  • 186 grams

  • 194 grams

  • 192 grams

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Solution

186 grams

Explanation:

Eldest daughter-in-law = 66 gm of gold

Youngest daughter-in-law has = 40 gm of gold

Middle daughter-in-law has = 80 gm of gold

Altogether they have = 66 + 40 + 80 gm of gold
                                   = 186 gm of gold
Therefore, daughter has = 186 gm of gold

Concept: Direction and Distance Test (Entrance Exam)
  Is there an error in this question or solution?
2015-2016 (May) Set 1

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