Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads

An observer 1.5m tall is 30 away from a chimney. The angle of elevation of the top of the chimney from his eye is 60 . Find the height of the chimney.

Advertisement Remove all ads

#### Solution

Let CE and AD be the heights of the observer and the chimney, respectively.

We have,

BD = CE = 1.5 m, BC = DE = 30 mand ∠ACB = 60°

In ΔABC

`tan 60° = (AB)/(BC)`

`⇒ sqrt(3 ) = (AD-BD)/30`

`⇒ AD -1.5 =30 sqrt(3)`

`⇒ AD = 30sqrt(3) +1.5`

`⇒ AD = 30XX 1.732 + 1.5`

`⇒ AD = 51.96 + 1.5`

`⇒ AD = 53.46 m`

So, the height of the chimney is 53.46 m (approx).

Concept: Heights and Distances

Is there an error in this question or solution?