Short Note

Sum

An object takes 5 s to reach the ground from a height of 5 m on a planet. What is the value of g on the planet?

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#### Solution

Here, *u* = 0 *S* = 5 m*t* = 5 s

From second equation of motion, we have

\[S = ut + \frac{1}{2}g t^2 \]

\[5 = \frac{1}{2}g(5 )^2 \]

\[g = \frac{10}{25} = 0 . 4 m/ s^2\]

Hence, the value of *g* on the planet is 0.4 m/s^{2}.

Concept: Variation in Value of g

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