Answer 1

 Here, u = 0 
S = 5 m
t = 5 s
From second equation of motion, we have

\[S = ut + \frac{1}{2}g t^2 \]
\[5 = \frac{1}{2}g(5 )^2 \]
\[g = \frac{10}{25} = 0 . 4 m/ s^2\]

Hence, the value of g on the planet is 0.4 m/s².