An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharp focussed image can be obtained? Find the size and nature of image.
Distance of the object from the mirror 'u' = −27 cm
Height of the object 'ho' = 7 cm
Focal length of the mirror 'f' = −18 cm
We have to find the distance of the image 'v' and height of the image 'hi'.
Using the mirror formula, we get
⇒ v=-54 cm
Thus, the distance of the image 'v' is 54 cm.
Now, using the magnification formula, we get
Therefore, the height of the image 'hi' is 14 cm.
Again, using the magnification formula, we get
Thus, the image is real, inverted and large in size.
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