Sum

An object *P* is focussed by a microscope *M*. *A* glass slab of thickness 2.1 cm is introduced between *P* and *M*. If the refractive index of the slab is 1.5, by what distance should the microscope be shifted to focus the object again?

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#### Solution

Given,

Thickness of the glass slab, *d* = 2.1 cm

Refractive index, μ = 1.5

Shift due to the glass slab is given by,

\[∆ t = \left[ 1 - \left( \frac{1}{\mu} \right) \right]d\]

\[= \left[ 1 - \left( \frac{1}{1 . 5} \right) \right]\left( 2 . 1 \right)\]

\[= \frac{1}{3}\left( 2 . 1 \right) = 0 . 7 cm\]

Hence, the microscope should be shifted by 0.70 cm to focus the object '*P*' again.

Concept: Refraction

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