Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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# An Object P Is Focussed by a Microscope M. A Glass Slab of Thickness 2.1 Cm is Introduced Between P And M. - Physics

Sum

An object P is focussed by a microscope MA glass slab of thickness 2.1 cm is introduced between P and M. If the refractive index of the slab is 1.5, by what distance should the microscope be shifted to focus the object again?

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#### Solution

Given,
Thickness of the glass slab, d = 2.1 cm
Refractive index, μ = 1.5
Shift due to the glass slab is given by,
$∆ t = \left[ 1 - \left( \frac{1}{\mu} \right) \right]d$
$= \left[ 1 - \left( \frac{1}{1 . 5} \right) \right]\left( 2 . 1 \right)$
$= \frac{1}{3}\left( 2 . 1 \right) = 0 . 7 cm$
Hence, the microscope should be shifted by 0.70 cm to focus the object 'P' again.

Concept: Refraction
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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 18 Geometrical Optics
Q 17 | Page 413
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