Tamil Nadu Board of Secondary EducationHSC Science Class 11

An object at an angle such that the horizontal range is 4 times the maximum height. What is the angle of projection of the object? - Physics

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Sum

An object at an angle such that the horizontal range is 4 times the maximum height. What is the angle of projection of the object?

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Solution

Given,

Horizontal range = 4Hmax

Solution:

Horizontal range = `(u^2 sin2theta)/g = (2u^2 sintheta costheta)/g`

Maximum height = `(u^2 sin^2theta)/(2g)`

as given `(2u^2 sin theta costheta)/g = (4u^2 sin^2theta)/(2g)`

2 cosθ = 2 sinθ

tanθ = 1

∴ θ = 45°

Concept: Projectile Motion
  Is there an error in this question or solution?
Chapter 2: Kinematics - Evaluation [Page 101]

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