An object 3 cm high is placed at a distance of 8 cm from a concave mirror which produces a virtual image 4.5 cm high:
(i) What is the focal length of the mirror?
(ii) What is the position of image?
(iii) Draw a ray-diagram to show the formation of image.
Distance of the object from the mirror 'u' = -8 cm
Height of the object 'ho' = 3 cm
Height of the image 'hi' = 4.5 cm
We have to find the focal length of the mirror 'f' and distance of the image 'v'.
Using the magnification formula, we get
Therefore, the distance of the image 'v' is 12 cm behind the mirror.
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