An object 3 cm high is placed 24 cm away from a convex lens of focal length 8 cm. Find by calculations, the position, height and nature of the image.
Object distance (u) =-24
Focal length (f) = +8
Object height (h) = 3 Lens formula is given by:1f=1v-1u⇒18=1v-1-24⇒18=1v+124⇒18-124=1v⇒3-124=1v⇒224=1v ⇒ v=12 cm Image will be form at a distance of 12 cm on the right side of the convex lens.Magnification m=vu ⇒ m=12-24
⇒m=-12So, the image is diminished. Negative value of magnification shows that the image will be real and inverted.">
Lens formula is given by :
Image will be form at a distance of 12 cm on the right side of the convex lens.
Magnification m `v/u`
so, the image is diminished
Negative value of magnification shows that the image will be real and inverted.
Hight of the image will be 1.5 cm Here, negative sign shows that the image will be in the downard direction
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