An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
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Solution
Let the third side of this triangle be x.
Perimeter of triangle = 30 cm
12 cm + 12 cm + x = 30 cm
x = 6 cm
`s="Perimeter of triangle"/2=30/2=15 cm`
By Heron's formula,
`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`
`=[sqrt(15(15-12)(15-12)(15-6))]cm^2`
`=[sqrt(15(3)(3)(9))]`
`=9sqrt15 cm^2`
Concept: Area of a Triangle by Heron's Formula
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