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An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle. - Mathematics

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An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

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Solution

Let the third side of this triangle be x.

Perimeter of triangle = 30 cm

12 cm + 12 cm + x = 30 cm

x = 6 cm

`s="Perimeter of triangle"/2=30/2=15 cm`

By Heron's formula,

`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`

                          `=[sqrt(15(15-12)(15-12)(15-6))]cm^2`

                          `=[sqrt(15(3)(3)(9))]`

                          `=9sqrt15 cm^2`

 

Concept: Area of a Triangle by Heron's Formula
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APPEARS IN

NCERT Class 9 Maths
Chapter 12 Heron's Formula
Exercise 12.1 | Q 6 | Page 203

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