Question

An iron rod of the area of cross-section 0.1m² is subjected to a magnetizing field of 1000 A/m. Calculate the magnetic permeability of the iron rod. [Magnetic susceptibility of iron = 59.9, magnetic permeability of vacuum = 4π x 10^-7 S. I. unit]  

An iron rod of the area of cross-section 0.1 m² is subjected to a magnetizing field of 1000 A/m. Calculate the magnetic permeability of the iron rod.

(χ for iron = 599 , µ₀ = 4π × 10^-7 SI unit)   

Answer 1

Given:- H= 1000 A/m, χ = 59.9, μ₀ = 4π x 10^-7 S.I. unit

To find:- Permeability (μ)

Formula:- μ = μ₀ (1 + χ)

Calculation:- From formula,

μ = 4π x 10^-7 (1 + 59.9)

   = 4 x 3.142 x 10^-7 x 60.9

   = antilog [log(4) + log(3.142) + log(60.9)] x 10^-7

   = antilog [0.6021 + 0.4972 + 1.7846] x 10^-7

   = antilog [2.8839] x 10^-7

   = 765.4 x 10^-7

∴ μ = 7.654 x 10^-5 Wb/A-m

The magnectic permeability of the iron rod is 7.654 x 10^-5 Wb/A-m.

Answer 2

Given:

H = 1000 A/m, χ = 599,
μ₀ = 4π × 10^-7 S.I. unit 

To find: Permeability (μ)

Formula: μ = μ₀(1 + χ) 

Calculation:

From formula,

μ = 4π × 10^-7 (1 + 599)

= 4 × 3.142 × 10^-7 × 600 

∴ μ = 7.54 × 10^-4 Hm^-1  

The magnetic permeability of the iron rod is 7.54 × 10^-4 Hm^-1.