Answer in Brief

An iron pole consisting of a cylindrical portion 110 cm high and of base diameter 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that 1 cm^{3} of iron has 8 gram mass approximately. (Use : π = 355/115)

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#### Solution

Volume of cylinder

`=pir^2 h`

`=22/7 xx 6 xx 6 xx 110`

`=12445. 714 cm^3`

Volume of cone

`=1/3pir^2h`

`=1/3 xx 22/7 xx 6 xx 6 xx 9`

`=339.429 cm^3`

Therefore,

Total volume

`=12445.714 +339.429`

`=12785 . 123 cm^3`

Therefore,

Mass of the pole

` =8 xx 12785.143 cm^3`

`= 102281.12 cm`

`= 102.28kg`

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