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An instrument manufactured by a company consists of two parts A and B in manufacturing part A, 9 out of 100 are likely to be defective and in manufacturing part B, 5 out of 100 are likely to be defective. Calculate the probability that both the instruments will not be defective.

#### Options

0 .91

0.86

0.95

0.83

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#### Solution

**0.86Explanation:**

Given, part A is not defective P(A) = `91/100`

and part B is not defective, P(B) = `95/100`

∴ Required probability = P(A) x P(B)

= `91/100xx95/100`

= 0.8645 = 0.86

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