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An engineer designs a satellite dish with a parabolic cross-section. The dish is 5m wide at the opening, and the focus is placed 1 2. m from the vertex. Position a coordinate system with the origin at the vertex and the x-axis on the parabola’s axis of symmetry and find an equation of the parabola

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#### Solution

Consider the satellite dish is open rightward parabola

y^{2} = 4 ax ........(1)

Clearly a = 1.2 m

(1) ⇒ y^{2} = 4(1.2)

y^{2} = 4.8x

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