Numerical

An engine does 54,000 J of work by exerting a force of 6000 N on it. What is the displacement in the direction of the force?

Advertisement Remove all ads

#### Solution

Given work done = 54,000J, force = 6000 N, 0 = 0°

Now work done = force x displacement x cos 0°

or displacement = `54000/6000` = 9m

Concept: Work, Energy, Power - Relation with Force

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads