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# An Elevator Descends into a Mine Shaft at the Rate of 6 M/Min. If the Descent Starts from 10 M Above the Ground Level, How Long Will It Take to Reach − 350 M. - CBSE Class 7 - Mathematics

ConceptProperties of Division of Integers

#### Question

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach − 350 m.

#### Solution

Distance descended is denoted by a negative integer.

Initial height = +10 m

Final depth = −350 m

Total distance to be descended by the elevator = (−350) − (+10) = −360 m

Time taken by the elevator to descend −6 m = 1 min

Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6)

= 60 minutes = 1 hour

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#### APPEARS IN

NCERT Solution for Mathematics for Class 7 (2018 to Current)
Chapter 1: Integers
Ex. 1.40 | Q: 7 | Page no. 26
Solution An Elevator Descends into a Mine Shaft at the Rate of 6 M/Min. If the Descent Starts from 10 M Above the Ground Level, How Long Will It Take to Reach − 350 M. Concept: Properties of Division of Integers.
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