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An Element `""_Zs^A` Decays to `""_85r^222` After Emitting 2 α Particles and 1 β Particle. Find the Atomic Number and Atomic Mass of the Element S. - Physics

An element `""_ZS^A` decays to `""_85R^222` after emitting 2 α particles and 1 β particle.

Find the atomic number and atomic mass of the element S.

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Solution

`""_ZS^A -> ""_85R^222 + 2(""_2^4He) + 1   ""_"-1"^0e`

A = 222 + 2(4) + 0

∴ A = 230

Z = 85 + 2(2) + (-1)

∴ Z = 88

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