# An electron in an atom is revolving around the nucleus in a circular orbit of radius 5.3 x 10-11 m, with a speed of 2 x 106 m/s. - Physics

Sum

An electron in an atom is revolving around the nucleus in a circular orbit of radius 5.3 x 10-11 m, with a speed of 2 x 106 m/s. Find the resultant orbital magnetic moment and angular momentum of the electron. [e = 1.6 x 10-19 C, me= 9.1 x 10-31 kg]

#### Solution

Data: r = 5.3 × 10-11 m, v = 2 × 106 m/s,

e = 1.6 × 10-19 C, me = 9.1 × 10-31 kg

The orbital magnetic moment of the electron is

"M"_0 = 1/2evr

= 1/2(1.6 xx 10^-19)(2xx10^6)(5.3 xx 10^-11)

= 8.48 × 10-24 A.m2

The angular momentum of the electron is

L0 = mevr

= (9.1 × 10-31)(2 × 106)(5.3 × 10-11)

= 96.46 × 10-36 = 9.646 × 10-35 kg.m2/s

Concept: Origin of Magnetism in Materials
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#### APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 11 Magnetic Materials
Exercises | Q 6 | Page 264