# An Electron Enters a Uniform Magnetic Field B=0.23x10-2 Wb/M2 at 450 Angle to B. Determine the Radius and Pitch of Helical Path. Assume Electron Speed to Be 3x107 M/S. - Applied Physics 2

Sum

An electron enters a uniform magnetic field B=0.23x10-2 Wb/m2 at 450 angle to B. Determine the radius and pitch of helical path. Assume electron speed to be 3x107 m/s.

#### Solution

Given:- B=0.23x10-2 Wb/m2

v=3x107 m/s

e=1.6x10-19 C

m=9.1x10-31 kg

Formula: R=mv/eB

R=(9.1×10^(−31)×3×10^7)/(1.6×10^(−19)×0.23×10^(−2))

R=0.074 m

Thus the radius of helical path is 0.074m.

Concept: Motion of Electron in Electric Field
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