MCQ
An electron of energy 150 eV has wavelength of 10-10m. The wavelength of a 0.60 keV electron is?
Options
0.50 Å
0.75 Å
1.2 Å
1.5 Å
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Solution
0.50 Å
`λ = h/sqrt(meV)`
`λ_1 α 1/sqrt(v_1)`
`λ_2 α 1/sqrt(v_2)`
`λ_1 / λ_2 = sqrt(v_2/v_1)`
`10^-10/λ_2 = sqrt(0.60xx10^3)/150`
`= sqrt(600/150) = 2`
`10^-10/λ_2 = 10^-10/2`
`= 0.5 xx 10^-10m`
`λ_2 = 0.5À`
Concept: de-Broglie Relation
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