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An electron is confined in a box of dimension 1A°. calculate minimum uncertainty in its velocity . - Applied Physics 1

Short Note

An electron is confined in a box of dimension 1A°. calculate minimum uncertainty in its velocity.

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Solution

Given Data :-  L = 10-10

Formula :- ∆Xma.∆pmi = ħ


Calculations :- since the electron is probable anywhere within the box of length 10-10 m, the maximum uncertainty in locating it is,

ΔXma = 10-10 m

ΔXma .m.ΔVmi = h

`ΔV _(mi) = h/(mΔX_(ma))`

`=(6.63 xx 10^(-34))/(2xx3.14xx9.1xx10^(-31)xx10(-8)`

`= ΔV_(mi) = 1.16xx 10^5 m⁄ sec`

Answer :- minimum uncertainty in velocity = 1.16×105m/s 

Concept: Applications of Uncertainty Principle
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