#### Question

An electron, an alpha particle and a proton have the same kinetic energy.

Which one of these particles has the largest de-Broglie wavelength?

#### Solution

De-Broglie’s wavelength is given as, λ = `h/(sqrt(2mK))`

Where, h is Planck’s constant, *m* is the mass of the particle, *K* is the kinetic energy of the particle

The mass of the electron is least among an electron, an alpha particle, and a photon.

`because lambda ∝ 1/sqrtm`, therefore, the electron has the largest de-Broglie wavelength.

Is there an error in this question or solution?

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An electron, an alpha particle and a proton have the same kinetic energy. Which one of these particles has the largest de-Broglie wavelength? Concept: de-Broglie Relation.

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