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An Electric Motor Raises a Load of 0.2 Kg, at a Constant Speed, Through a Vertical Distance of 3.0 M in 2 S. If the Acceleration of Free Fall is 10 M/S2, the Power in W Developed - Science

MCQ

An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0 m in 2 s. If the acceleration of free fall is 10 m/s2, the power in W developed by the motor in raising the load is :

Options

  • 0.3

  • 1.2

  • 3.0

  • 6.0

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Solution

Mass of the load (m1) = 0.2 kg
Height (h) = 3 m
Acceleration due to gravity (g) =10 m/s2
Time taken  (t) = 2s
We can calculate the work done against gravity as,
 Work done by the car = (Weight of body) (Vertical distance)
                                    = (0.2)(10)(3) J
                                    = 6 J
Now, we can calculate the power of the boy as,
Power = `"Work done"/"Time"`
So , 
Power = `6/2` W
= 3 W
So, the power is 3 W.
Therefore, the answer is, (c) 3.0

  Is there an error in this question or solution?
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APPEARS IN

Lakhmir Singh Science Class 9 Physics
Chapter 4 Work and energy
MCQ | Q 40 | Page 164
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